Respuesta :
Answer:
Impulse, J = 6.52 kg-m/s
Explanation:
Given that,
Mass of the baseball, m = 0.145 kg
Initially, the baseball is at rest, u = 0
Final speed of the baseball, v = 100.9 mi/hr = 45 m/s
To find,
Impulse required to give baseball such a momentum.
Solution,
Impulse delivered to the baseball is give by the change in its momentum. It is given by :
[tex]J=m(v-u)[/tex]
[tex]J=mv[/tex]
[tex]J=0.145\ kg\times 45\ m/s[/tex]
J = 6.52 kg-m/s
So, the impulse delivered to the baseball is 6.52 kg-m/s.
The impulse required to give a 0.145 kg baseball such momentum is 6.525 N
Given that:
the change in the pitch Δv = 45 m/s
the mass of the baseball m = 0.145 kg
The impulse is the specific amount of force applied over a certain period of time to induce a change in momentum.
Impulse = m × Δv
Impulse = 0.145 kg × 45 m/s
Impulse = 6.525 N
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