According to the Guinness Book of World Records, the fastest recorded baseball pitch was delivered by Nolan Ryan in 1974. The pitch was clocked at 100.9 mi/hr (45.0 m/s). Determine the impulse required to give a 0.145-kg baseball such a momentum.?

Respuesta :

Answer:

Impulse, J = 6.52 kg-m/s

Explanation:

Given that,

Mass of the baseball, m = 0.145 kg

Initially, the baseball is at rest, u = 0

Final speed of the baseball, v = 100.9 mi/hr = 45 m/s

To find,

Impulse required to give baseball such a momentum.

Solution,

Impulse delivered to the baseball is give by the change in its momentum. It is given by :

[tex]J=m(v-u)[/tex]

[tex]J=mv[/tex]

[tex]J=0.145\ kg\times 45\ m/s[/tex]

J = 6.52 kg-m/s

So, the impulse delivered to the baseball is 6.52 kg-m/s.

The impulse required to give a 0.145 kg baseball such momentum is 6.525 N

Given that:

the change in the pitch Δv = 45 m/s

the mass of the baseball m = 0.145 kg

The impulse is the specific amount of force applied over a certain period of time to induce a change in momentum.

Impulse = m × Δv

Impulse = 0.145 kg × 45 m/s

Impulse = 6.525 N

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