Question

"calculate the ratio of the velocity of hydrogen molecules to the velocity of carbon dioxide molecules at the same temperature"

Answer 1

Answer: 1:4.69

Explanation:

The ratio can be expressed as:

Ua/Ub= √(Mb/Ma)

Where Ua/Ub is the ratio of velocity of hydrogen to carbon dioxide and Ma is the molecular mass of hydrogen gas= 2

Mb is the molecular mass of CO2 = 44

Therefore

Ua/Ub= √(44/2)

Ua/Ub = 4.69

Therefore the ratio of velocity of hydrogen gas to carbon dioxide = 1:4.69

which implies hydogen is about 4.69 times faster than carbon dioxide.

Answer 2

The ratio of the velocity of hydrogen molecules to Carbon dioxide at same temperature is :  1 : 4.7

Determine the ratio of the velocity of hydrogen molecule to carbon dioxide

Applying the expression below given that temperature is constant

$\frac{Ua}{Ub} = \sqrt{\frac{Mb}{Ma} }$  ----- ( 1 )

M = molecular masses of C0₂ and Hydrogen

U = velocity

a = hydrogen , b = C0₂

Back to equation ( 1 )

$\frac{Ua}{Ub} = \sqrt{\frac{44}{2} }$   = 4.69 ≈ 4.7

Therefore we can conclude that the ratio of the velocity of hydrogen molecules to Carbon dioxide at same temperature is :  1 : 4.7

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