Answer:
The answer is 2i on right hand side.
Explanation:
We should star by checking the equation from right.
First we check how many Zn r there in left hand side. Which is 1. Let us check how many Znr there in right hand side, there is 1.So Zn is balanced, and don't worry about Znplus2 on right hand side it is just the ions not how many zinc r there.
Now let us check how many I are there left hand side. Which is 2. Now how many I are there in right hand side? Only 1.
So we put 2 behind I.
Now there r 2 I on both sides.
Its simple actually.
Answer:
Zn + I2 > Zn+² + 2 I-
Explanation:
First identify the which is oxidised and reduced in the reaction.
Zn > Zn2+ is oxidised increase in ox. #
I2 > 2I- is reduced decrease in ox. #
Do half reactions and add electrons to each positive side to balance the charges
Zn > Zn2+ + 2e-
I2 + 2e- > 2 I-
Combine each product side and reactant. Cancel the electrons out since they are in the same amount.
