Question

Which of these are the intercepts of the graph of y=3x-12

A. (4, 0) ,(0, -12)
B.(12 ,0), (0,4)
C.(3, 0), (0, 4)
D.(4, 0), (0, 3)
E.(-4, 0), (0, -12)

Answer 1

The equation of the linear function is given in the form of a directional
equation consists of solid :
1.współczynniki a and b .
2. The variables x and y

y=  3x - 12
y = ax + b 
a = 3      (the slope of the tangent to the x-axis)
b = - 12  (intersection of the axis y)
we look for the point ( 0 , -12 ) because b = -12

A. (4, 0) ,(0, -12)
B.(12 ,0), (0,4)
C.(3, 0), (0, 4)
D.(4, 0), (0, 3)
E.(-4, 0), (0, -12)

fit and answers a,e

we set the coordinate system and you activate the point ( 0 , -12 )
Now draw a straight line parallel to the x axis przchodzącą through the point (0 , -12 )
We notice that a> 0 the function is increasing

We draw a line parallel to the triangle . Invent lengths of the sides 3 : 1. Examples are a = b = 1cm 3cm and 6cm a = b = 2 cm .

the hypotenuse of the triangle is our simple
Intersection of the axis x = ( 4,0 )

Answer A

Answer 2

Answer:

(4, 0) ,(0, -12)

Step-by-step explanation:

The given linear equation is $y=3x-12$

For x-intercept, y =0

$0=3x-12\\\\3x=12\\\\x=\frac{12}{3}\\\\x=4$

Hence, the x intercept is at (4,0)

For y-intercept, x =0

$y=3(0)-12\\\\y=0-12\\\\y=-12$

Hence, the y intercept is at (0,-12)

Therefore, the intercepts of the graph of the given equation are(4, 0) ,(0, -12)