The work done is 400 J
Explanation:
The work done by you in pushing the box along the slope is given by
[tex]W=Fd[/tex]
where
F is the magnitude of the force applied
d is the distance covered by the box along the slope
Here we have the following:
F = 200 N is the magnitude of the force applied
[tex]d=\frac{h}{sin \theta}[/tex] is the distance covered, where
h = 1 m is the vertical rise
[tex]\theta=30^{\circ}[/tex] is the slope of the plane
Substituting and solving, we find
[tex]W=F\frac{h}{sin \theta}=\frac{(200)(1)}{sin 30^{\circ}}=400 J[/tex]
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