Question

Assume we have a mechanical hard drive with the following characteristics:

Number of surfaces - 2 (this is a double-sided disk, a single read/write arm holds both read write heads)
Number of tracks per surface - 500
Number of sectors per track - 20
Number of bytes per sector - 1024

In general, information is stored on a disk not at random but in specific locations that help to minimize the time it takes to retrieve that information. Using the specifications above, where would you store the information in a 50 KB file on the disk to speed up subsequent access to that information.

Answer 1

Explanation:

Given:

Surface = 2

Track per surface = 500

Sector per track = 20

Bytes per sector = 1024

We have to store 50 kb file then, required the numbers of sector:

             $\frac{50\times 1024}{1024}=50$

Then, we have the number of sectors in 1: $500 \times 20=1000$

  $\therefore The\,\, surface\,\, number:\\ \:\:50 \div 1000$

Then, the remainder = 50 i.e., sector number

Then, the quotient = 0 i.e., surface number

 $\therefore \,the \,\,sector \,\,number:\\ \:\:50 \div 20$

Then, the remainder = 10 i.e., sector number

Then, the quotient = 2 i.e., track number number

$Finally, \, files\,\, is \, stores\, at \,the \,<0,2,10> locations$