Answer:
probability of the child having attached earlobes since it is recessive i.e (yy)
=1/4
=0.25 × 100%
=25%
Explanation:
If two heterozygous individuals have a child
i.e let the heterozygous individuals be = Xy
if both traits crosses together; their F₁ offspring will be; (XX, Xy, Xy, yy)
Xy × Xy
X y
X XX Xy
y Xy yy
probability of the child having attached earlobes since it is recessive i.e (yy)
=1/4
=0.25 × 100%
=25%
