Question

Wave Properties
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Calculating Frequency
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A hummingbird can flutter its wings 4,800 times per minute.
What is the frequency of wing flutters per second?
flutters/second
What is the period for one wing flutter in seconds?

Answer 1

Answer:

f = 80  flutter/ second

T= 0.0125 sec

Explanation:

Given data:

Fluttering of wings = 4800 time per minute

Frequency of wings = ?

Period for one wing in sec = ?

Solution:

There are 60 seconds in one minute, thus frequency of wings

4800/60 = 80  flutter per second

Period:

T = 1/f

T = 1/80

T= 0.0125 sec

Answer 2

Answer:

flutters per second is 80 and the period is 0.013.

Explanation:

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