Answer:
Area of the trapezoid is 278.63 square units.
Step-by-step explanation:
In this question figure of the trapezoid is not given;
If the figure is same as figure attached,
FKLM is the trapezoid having
Side FK = 10 units
KL = 26 units
m∠F = 48°
Now in ΔKFP,
sin48° = [tex]\frac{PK}{FK}[/tex]
0.7431 = [tex]\frac{PK}{10}[/tex]
PK = 7.43 units
Now area of the trapezoid FKLM = [tex]\frac{1}{2}(\text{sum of parallel sides)}(\text{distance between parallel sides})[/tex]
= [tex]\frac{1}{2}(26+49)(7.43)[/tex]
= 278.63 square units
Therefore, area of the trapezoid will be 278.63 square units.
