Answer:
a) p is normally distributed with mean P = 0.4 and standard deviation
δ = 0.05477
b) P( 0.3 < p < 0.5) = 0.9312
Step-by-step explanation:
a) What is the sampling distributión of P?
p(sample proportion) is normally distributed with mean P and standard
deviation δ = [tex]\sqrt{\frac{P(1-P)}{n} }[/tex]
how P = 0.40 population proportion of the students live in dormitories,
then p is normally distributed with mean P = 0.4 and standard deviation
δ = [tex]\sqrt{\frac{0.4(1-0.4}{80} }[/tex]
δ = 0.05477
b) P( 0.3 < p < 0.5)
Standardizing
z = (p - P)/δ
[tex]z_{1} = \frac{0.3-0.4}{0.05477}[/tex]
= -1.82
[tex]z_{2} = \frac{0.5-0.4}{0.05477}[/tex]
= 1.82
P(-1.82 < z < 1.82) = P(z < 1.82) - P(z<-1.82)
=0.9656 - 0.0344
P(-1.82 < z < 1.82) = 0.9312