Answer:
The Two points for the line [tex]y =\frac{-1}{2}x+4[/tex] are
point A( x₁ , y₁) ≡ ( 0 , 4)
point B( x₂ , y₂) ≡ (8 , 0)
The Graph is attached below.
Step-by-step explanation:
Given:
[tex]y =\frac{-1}{2}x+4[/tex]........... equation of a line Given
Let the points be point A, and point B
To Find:
point A( x₁ , y₁) ≡ ?
point B( x₂ , y₂) ≡ ?
Solution:
For Drawing a graph we require minimum two points but we will have here.
For point A( x₁ , y₁)
Put x = 0 in the given equation we get
[tex]y =\frac{-1}{2}0+4\\\\y=4[/tex]
∴ point A( x₁ , y₁) ≡ ( 0 , 4)
For point B( x₂ , y₂)
Put y= 0 in the given equation we get
[tex]0 =\frac{-1}{2}x+4\\\\x=8[/tex]
∴ point B( x₂ , y₂) ≡ (8 , 0)
Therefore,
The points for the line [tex]y =\frac{-1}{2}x+4[/tex] are
point A( x₁ , y₁) ≡ ( 0 , 4) (blue color point on the graph)
point B( x₂ , y₂) ≡ (8 , 0) (green color point on the graph)
The Graph is attached below..