Respuesta :
The two numbers are 24 and 50
Solution:
Let the bigger number be "b"
Let the smaller number be "s"
Given that sum of a number and two times a smaller number is 98
We can frame a equation as:
bigger number + two times a smaller number = 98
b + 2s = 98 ----- eqn 1
Also given that bigger number is 22 less than three times the smaller number
bigger number = 22 less than three times the smaller number
bigger number = three times the smaller number - 22
b = 3s - 22 ----- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "b" and "s"
Substitute eqn 2 in eqn 1
3s - 22 + 2s = 98
5s - 22 = 98
5s = 98 + 22
5s = 120
s = 24
Substitute s = 24 in eqn 2
b = 3(24) - 22
b = 72 - 22
b = 50
Thus the two numbers are 24 and 50
