Answer:
It takes the pulse 25.1 ms to travel the 9.00 m of the string
Explanation:
Force (F) = Mass( m) × Acceleration.( a)
F = ma............... equation 1
Making a the subject of equation 1 above,
a = F/m .............. equation 2
Where F = T = 200 N, m = 7.00 g = 0.007 kg,
Substituting these values into equation 2,
a = 200/0.007 = 28571.43 m/s².
Using one of the equation of motion,
S = ut + 1/2at²................... equation 2
Where S = distance, u = initial velocity, t = time, a = acceleration.
u = 0.
Therefore, S = 1/2at²................. equation 3
Making t the subject of equation 3,
t = √ (2S/a).................. equation 4
Where S = 9.00 m , a = 28571.43 m/s²
Substituting this values into equation 4,
t = √{(2×9)/28571.43}
t = √(18/28571.43
t = √0.00063
t = 0.0251 s
t = 25. 1 ms
Therefore it takes the pulse 25.1 ms to travel the 9.00 m of the string.
