Answer:
-V(X + c) = V(X) + c
Step-by-step explanation:
Using the propierties of the variance:
[tex]Var(k)=0[/tex]
Where k is an arbitrary constant. So:
-V(c) = 0 is true.
[tex]Var(kX)=k^2V(X)[/tex]
Where k is an arbitrary constant. Therefore:
-V(cX) = c2 V(X) is true.
[tex]Var(X+k)=V(X)[/tex]
Where k is an arbitrary constant. Hence:
-V(X + c) = V(X) + c is not true.