Question

A blackbody has a
surface area of 2.00 m^2.
Find the energy emitted
per minute from this
area if the temperature
is 398 K. Express the
answer in joules. The
Stefan-Boltzmann
constant is 5.67 × 10^-8 W/m^2•K^4

Answer 1

The energy emitted per minute by the blackbody at the given area is 170,724.8 J/min.

Energy emitted per minute

The energy emitted per minute at the given area is calculated as follows;

P = σAT⁴

P = (5.67 x 10⁻⁸) x (2) (398)⁴

P = 2845.41 W = 2845.41 J/s

Convert energy emitted per second to per minutes

P = 2845.41 J/s x (60 s / min) = 170,724.8 J/min

Thus, the energy emitted per minute by the blackbody at the given area is 170,724.8 J/min.

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