To solve this problem it is necessary to apply the concepts related to the electric field as a function of voltage and distance, the magnetic field as a function of the speed of light and the electric field and finally the wavelength whose definition is based on the speed of light and frequency.
PART A) The maximum electric field strength produced is,
[tex]E_{max} = \frac{V_{max}}{d}[/tex]
[tex]E_{max} = \frac{4mV}{0.4m}[/tex]
[tex]E_{max} = \frac{4*10{-3}V}{0.4m}[/tex]
[tex]E_{max} = 0.01V/m[/tex]
Therefore the maximum electric field strnegth produced is 0.01V/m
PART B) The maximum magnetic field strength in the electromagnetic wave is
[tex]B_{max} = \frac{E_max}}{c}[/tex]
[tex]B_{max} = \frac{0.01V/m}{3*10^8m/s}[/tex]
[tex]B_{max} = 3.33*10^{-11}T[/tex]
Therefore the corresponding maximum magnetic field strengthintheelectromagnetic wave is [tex]3.33*10^{-11}T[/tex]
PART C) Wavelength of electromagnetic wave is,
[tex]\lambda f = c[/tex]
[tex]\lambda = \frac{c}{f}[/tex]
[tex]\lambda = \frac{3*10^8m/s}{1Hz}[/tex]
[tex]\lambda = 3*10^8m[/tex]
Therefore the wavelength of the electromagnetic wave [tex]3*10^8m[/tex]