Question

Aspirin (C9H8O4) may be synthesized by mixing salicylic acid (C7H6O3) with excess acetic anhydride (C4H6O3).
The balanced equation is C7H6O3 + C4H6O3 C9H8O4 + C2H4O2 When 2.0 g of salicylic acid is mixed with excess acetic anhydride, 1.7 g of aspirin is collected.

What is the percent yield for this reaction?

Answer 1

Answer:

65.18% is the percent yield for this reaction.

Explanation:

$C_7H_6O_3 + C_4H_6O_3\rightarrow C_9H_8O_4 + C_2H_4O_2$

Moles of salicyclic acid = $\frac{2.0 g}{138 g/mol}=0.01449 mol$

According to reaction 1 mole of salicyclic acid gives 1 mole of aspirin .

Then 0.01449 mole of salicylic acid will give :

$\frac{1}{1}\times 0.01449 mol=0.01449 mol$ of asprin

Mass of 0.01449 moles of aspirin :

= 0.01449 mol × 180 g/mol = 2.6082 g

Theoretical yield of aspirin = 2.6082 g

Experimental yield of aspirin = 1.7 g

The percent yield for this reaction:

$\%(Yield)=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$=\frac{1.7 g}{2.6082 g}\times 100=65.18\%$

65.18% is the percent yield for this reaction.