Question

For which pair of functions is the vertex of g(x) 11 units above the vertex of f(x)?
O A. f(x) = x2 and g(x) = (x + 11)2
O B. f(x) = x2 and g(x) = (x - 11)2
O c. f(x) = x2 and g(x) = x2 +11
O D. Rx) = x2 and g(x) = x2 - 11

Answer 1

Answer:

C

Step-by-step explanation:

Given f(x) then f(x) + c is a vertical translation of f(x)

• If c > 0 then a vertical shift up of c units

• If c < 0 then a vertical shift down of c units

Here g(x) is 11 units above, that is a shift up, thus

g(x) = f(x) + 11, that is

g(x) = x² + 11 → C

Answer 2

The quadratic equation g(x) that has a vertex 11 units above f(x) is given by:

c. f(x) = x² and g(x) = x² +11

What is the equation of a parabola given it’s vertex?

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)² + k

In which a is the leading coefficient.

For g(x) to have a vertex 11 units above f(x), we need for them to have an equal value of h, and k being 11 units greater for g(x), hence option C is correct.

More can be learned about quadratic equations at https://brainly.com/question/24737967

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