Question

Pls help, I need to get my test done b4 the end of today, and I still need to finish the rest of the questions!
(09.02 MC) Write x^2 − 8x + 13 = 0 in the form (x − a)2 = b, where a and b are integers.

Answer 1

The equation in required form is: $(x-4)^2 = 3$

Step-by-step explanation:

Given equation is:

$x^2-8x+13=0$

to write the equation in $(x-a)^2 = b$ form where a and b are integers

subtracting 13 from both sides

$x^2-8x+13-13=0-13\\x^2-8x = -13$

To complete the square:

2.x.b = 8x

b = 8x/2x = 4

So adding (4)^2 on both sides

$(x)^2-8x+(4)^2 = -13+(4)^2\\(x-4)^2 = -13+16\\(x-4)^2 = 3$

Hence,

The equation in required form is: $(x-4)^2 = 3$

Keywords: Quadratic equation, Vertex form

Learn more about quadratic equation at:

• brainly.com/question/10978510
• brainly.com/question/11007026

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