Respuesta :
For this case we propose a rule of three. We assume that the excess water received was in one day. So:
[tex]\frac {3} {4}[/tex] cup ------> 100%
x ----------------------------> 25%
Where "x" represents excess water.
[tex]x = \frac {25 * \frac {3} {4}} {100}\\x = \frac {\frac {75} {4}} {100}\\x = \frac {75} {400}\\x = \frac {15} {80}\\x = \frac {3} {16}[/tex]
Thus, the excess water is [tex]\frac {3} {16}[/tex]cups.
Then, in one day you receive in total:
[tex]\frac {3} {4} + \frac {3} {16} = \frac {16 * 3 + 4 * 3} {16 * 4} = \frac {48 + 12} {64} = \frac {60 } {64} = \frac {15} {4}[/tex]cups of water.
Answer:
[tex]\frac {15} {4}[/tex] cups of water