Answer:
[tex]3\frac{y}{x} + 2y^{7}[/tex]
Step-by-step explanation:
We have to simplify the expression as given below:
[tex]\frac{105x^{6}y^{5} + 70x^{7}y^{11}}{35x^{7}y^{4} }[/tex]
As we know that [tex]\frac{a + b}{c} = \frac{a}{c} + \frac{b}{c}[/tex]
= [tex]\frac{105x^{6}y^{5}}{35x^{7}y^{4}} + \frac{70x^{7}y^{11}}{35x^{7}y^{4}}[/tex]
As we know the property of exponent [tex]\frac{x^{a} }{x^{b} } = x^{a - b}[/tex]
= [tex]3x^{6 - 7}y^{5 - 4} + 2x^{7 - 7} y^{11 - 4}[/tex]
= [tex]3x^{-1}y^{1} + 2x^{0} y^{7}[/tex]
As we know the properties of exponents [tex]a^{-b} = \frac{1}{a^{b} }[/tex] and [tex]a^{0} = 1[/tex]
= [tex]3\frac{y}{x} + 2y^{7}[/tex] (Answer)
