Question

Glucose is present in blood plasma at a concentration of approximately 80 mg/dL. A typical 70 kg human has approximately 5 L blood, which is 55% plasma. Using the 44.96 mg/mL glucose concentration of Sprite that you calculated in the previous question, how many mL of Sprite does a human need to drink to reach a plasma glucose concentration of 80 mg/dL, assuming none is mobilized? (Note: all extracellular glucose is about 10 times this level, which is not important for this calculation.(Please pay attention to the units mg/dL)

Answer 1

Answer:

A human need to drink 48.93 mL of sprite  to reach a plasma glucose concentration of 80 mg/dL.

Explanation:

Volume of blood in 7 Kg human = 5 L

Percentage of plasma in blood = 55%

Volume of plasma in 5 L blood = $\frac{55}{100}\times 5 L=2.75 L=27.5 dL$ (1 L = 10 dL)

Concentration of glucose in plasma = 80 mg/dL

Amount of glucose present in 27.5 dL : 80 mg /dL × 27.5 dL= 2200 mg

Let the volume of sprite with 2200 mg glucose be x

Concentration of glucose in sprite = 44.96 mg/mL

$x\times 44.96 mg/mL=2200 mg$

$x=\frac{2200 mg}{44.96 mg/mL}=48.93 mL$

A human need to drink 48.93 mL of sprite  to reach a plasma glucose concentration of 80 mg/dL.