Question

A helium balloon is filled to a volume of 2.88 x 103 L at 722 mm Hg and 19°C. When the balloon is released, it rises to an altitude where the pressure and temperature are 339 mm Hg and -55oC, respectively. What is the volume of the balloon (in L)

Answer 1

Answer:

V₂=4.57 x 10³ L

Explanation:

Given that

V₁= 2.88 x 10³ L

P₁=722 mm  Hg

T₁ = 19°C

T₁ =292 K

P₂=339 mm Hg

T₂= - 55°C

T₂=218 K

Lets take final volume = V₂

We know that ideal gas equation

PV = m R T

By applying mass conservation

$\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}$

$\dfrac{722\times 2.88\times 10^3}{292}=\dfrac{339\times V_2}{218}$

V₂=4.57 x 10³ L

Therefore volume will be 4.57 x 10³ L