Question

I am driving 65 mph when I suddenly come to a stop. my acceleration was -9.2 m/s squared. how long did it take me to stop?
hint: convert mph to m/s first

Answer 1

The car takes 3.15 s to stop

Explanation:

The motion of the car is a uniformly accelerated motion (=constant acceleration), therefore we can use the following suvat equation:

$v=u+at$

where

v is the  final velocity

u is the initial velocity

a is the acceleration

t is the time

Keeping in mind that

1 mile = 1609 metres

1 hour = 3600 seconds

Here we have:

$u = 65 mph \cdot \frac{1609 m/mile}{3600 s/hour}=29.0 m/s$ is the initial velocity, converted into m/s

v = 0 is the final velocity (the car comes to a stop)

$a=-9.2 m/s^2$ is the acceleration

And solving the equation for t, we find

$t=\frac{v-u}{a}=\frac{0-29.0}{-9.2}=3.15 s$

Learn more about accelerated motion:

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