Answer:
[tex]v=1.307m/s[/tex]
Explanation:
The velocity of both animals are the same the analysis of the motion is:
[tex]E_{pr}-E_{pw}=K_{Ew}+K_{Er}[/tex]
[tex]E_{pw}=m*g*h[/tex], [tex]h=0.395 cm[/tex]
[tex]E_{pw}=0.510kg*9.8m/s^2*0.395m=197.421x10^{-3}J[/tex]
[tex]E_{pr}=m*g*h[/tex], [tex]h=0.395 cm[/tex]
[tex]E_{pr}=0.210kg*9.8m/s^2*0.395m=812.91x10^{-3}J[/tex]
Replacing in the initial equation now solve to velocity in this case is the same for both animals so:
[tex]615.489x10^{-3}J=\frac{1}{2}*v^2[0.51+0.21]kg[/tex]
[tex]v^2=\frac{1.2309J}{0.72kg}=1.709m^2/s^2[/tex]
[tex]v=1.307m/s[/tex]