A 4.9 ev photon strikes the surface of silver and an electron is emitted. The maximum possible speed of the electron is 3.5 × 10⁵ m/s
Energy of electron is the possible when a photon strikes the silver surface leading to emission of an electron.
We know that,
1/2mv² = Energy
where, m is the mass of electron
v is the velocity of electron
Given,
m = 9.1 × 10⁻³¹
Energy = 4.9 eV = 4.9 × 1.6 × 10⁻¹⁹
v = ?
On substituting the value in above formula,
1/2 9.1 × 10⁻³¹v² = 4.9 × 1.6 × 10⁻¹⁹
v = √4.9 × 1.6 × 10⁻¹⁹× 2 / 9.1 × 10⁻³¹
v = 3.5 × 10⁵ m/s
The maximum possible speed of the electron is 3.5 × 10⁵ m/s
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