Answer:
statement B is true
Explanation:
since same force is applied by the compressed spring on both masses so their rate of change of momenta must be same and since the lighter block has lesser mass so it must have greater velocity to have an equal change in momentum as of heavier mass.
By relation: [tex]KE=\frac{(mv)^{2} }{2m}[/tex]
[tex]KE lighter=\frac{(mv)^{2} }{2(1)}[/tex] , [tex]KEheavier=\frac{(mv)^{2} }{2(2)}[/tex]
comparing momenta of above two equations we get
KElighter (2) = KEheavier (4)
KElighter = 2 KEheavier