Question

Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 11 people took the trip. She was able to purchase coach tickets for ​$230 and first class tickets for ​$980. She used her total budget for airfare for the​ trip, which was ​$7780. How many first class tickets did she​ buy?How many coach tickets did she​ buy?number of first class tickets bought?number of coach tickets bought?

Answer 1

Answer:

Sarah purchased 4 coach tickets and 7 First class tickets.

Step-by-step explanation:

Let the total number of  coach tickets brought = x

Let the total number of first class ticket purchased=  y

⇒  x + y = 11

Also, cost of 1 coach ticket =  $230

So, the cost of x coach tickets  =  x ($230) = 230 x

And, cost of 1 first class ticket =  $980

So, the cost of y first class tickets  =  y ($980) = 980 y

The total allowance for the trip is = $7780

⇒   230 x + 980y =  $7780

Solving the given system of equation:

 x + y = 11

230 x + 980 y =  $7780

Substitute the value y =  11 -x in the second equation.

we get  :

230 x + 980 y =  $7780 ⇒  230 x + 980 (11 - x) =  $7780

or,  230 x + 10,780  - 980 x = 7780

or, -750 x =  -3000

or, x  = 3000/750 = 4

or, x  = 4

⇒ y = 11 - x  = 11 - 4 = 7

or, x = 4, y = 11 is the solution of the system.

Hence, Sarah purchased 4 coach tickets and 7 First class tickets.