Answer:
Equilibrium Concentration = 0.105mg/kg
Explanation:
Let initial concentration be C₀
S(aq) at initial = C₀ , S(s) at initial = 0
S(aq) at equilibrium = C₀ - Xe , S(s) at equilibrium = Xe
Xe = 1312.5 mg/kg
At equilibriuim Kd = [S(s)]/[S(aq)]
12500 = 1312.5/(C₀ - 1312.5)
C₀ = 1312.605 mg/kg
Equilibrium Concentration = 1312.605 - 1312.5 = 0.105mg/kg