Respuesta :
Answer:
Upper
if your asking that kind of question
Step-by-step explanation:
The confidence interval in which the difference in the weight lost by the two group lies using a confidence level of 95% is (0.891 ; 4.891)
The confidence interval for the mean difference is defined thus :
- Mean difference ± S.E
- degree of freedom, df = n1 + n2 - 2 = (500 - 2) = 498
- Critical level = t* at df = 498 = ±1.96
- Mean difference = (μ1 - μ2) = 7 - 5 = 2
Standard Error = [tex]t* \times \sqrt{\frac{s_{1}}^{2}{n_1} + \frac{s_{2}}^{2}{n_2}} = \sqrt{\frac{20^{2}}{250} + \frac{12^{2}}{250}} = 1.96 \times 1.475 = 2.891 [/tex]
Lower boundary = 2 - 2.891 = 0.891
Upper boundary = 2 + 2.891 = 4.891
Therefore, the confidence interval is (0.891 ; 4.891)
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