Answer:
t= 1.2 hours
Explanation:
Define first di distance between the points, so
[tex]\bar{x}_{canoe}=2*(2+3)=10[/tex]
[tex]\bar{x}_{water}=2*2=4[/tex]
The distance is
[tex]d= \bar{x}_{canoe}- \bar{x}_{water}[/tex]
[tex]d= 10-4 = 6miles[/tex]
[tex]t = \frac{x}{v} = \frac{6}{2+3}[/tex]
[tex]t= 1.2 hours[/tex]