Question

A submarine reaches the depth of 105 m (densi-
ty of sea water = 1030 kg/m

).
Calculate the absolute pressure that the subma-
rine need to be able to withstand.​

Answer 1

Answer:

The pressure the the submarine need to able to withstand is

P=1.161195 Mpa

P=1.161195$x10^{6}$ pa

Explanation:

$Pressure= (Density_{object} *Gravity*Depth_{object} )+Pressure_{atmosphere}\\Pressure_{atmosphere}=101325 pa \\\\P=(1030 \frac{kg}{m^{3}}*9.8\frac{m}{s^{2} }*105m)+ 101325 pa\\P=(1059870 \frac{kg*m^{2} }{m^{3}*s^{2}})+101325 pa\\P=(1059870 \frac{N}{m^{2}}+101325 pa\\ P=1059870 pa +101325 pa=1161195pa\\P=1.161x10^{6}pa\\ P=1.161Mpa$