Question

Mohammed has a box of coins containing only dimes
and half-dollars. There are 26 coins, and the total
value is $8.60. How many of each denomination of
coin does he have?

Answer 1

Answer:

Mohammed has 11 dimes and 15 half-dollars.

Step-by-step explanation:

Let x be the number of dimes and y be the number of half-dollars. There are 26 coins, then

$x+y=26$

Amount in dimes = 10x cents

Amount in half-dollars = 50y cents

Total amount = 10x + 50y cents

Thus,

$10x+50y=860$

Solve the system of two equations:

$\left\{\begin{array}{l}x+y=26\\10x+50y=860\end{array}\right.$

From the first equation

$x=26-y$

Substitute it into the second equation:

$10(26-y)+50y=860\\ \\26-y+5y=86\\ \\-y+5y=86-26\\ \\4y=60\\ \\y=15\\ \\x=26-15=11$

Mohammed has 11 dimes and 15 half-dollars.