Answer:
Explanation:
Given
initial speed [tex]=v_i[/tex]
coefficient of kinetic friction[tex]=\mu [/tex]
It moves a distance d after that it comes to rest
acceleration offered by table top[tex]=\mu g[/tex]
[tex]v^2-u^2=2as[/tex]
[tex]0-(v_i)^2=2(-\mu g)d[/tex]
[tex]v_i=\sqrt{2(\mu g)d}[/tex]