What is an equation in point-slope form of the line that passes through the point (4, −1) and has slope 6?

Respuesta :

the point-slope form of a line is given by: y - y1 = m(x - x1). Substituting the given point, (6, -8), and the slope, -2, gives:

y - (-8) = -2 * (x - 6)

This becomes:

y + 8 = -2x + 12

Answer:y+1=6(x-4)

Step-by-step explanation:

In the question you are already given the information needed, so you don't have to really solve anything further. All you have to do is input it into the point-slope form equation y-y1=m(x-x1) from x1=4 y1=-1 and m=6, giving you y+1=6(x-4). If you're wondering, I got the + in y+1 because of the two negatives being together giving you a positive.