Answer: 0.923
Step-by-step explanation:
Let A be the event an Internet user posts photos that they have taken themselves, and B be the event an Internet user posts videos that they have taken themselves.
Pew Research Center finds that
P(A)=0.52 P(b)=0.26, and P(A or B)=0.54.
To find : P(A|B)
Since , [tex]\text{P(A or B)=P(A+P(B)-P(A and B)}[/tex]
i.e. [tex]\text{P(A and B)=P(A)+P(B)-P(A or B)}[/tex]
[tex]\text{P(A and B)=}0.52+0.26-0.54=0.24[/tex]
Now, using conditional probability formula ,
[tex]P(A|B)=\dfrac{\text{P(A and B)}}{\text{P(B)}}\\\\=\dfrac{0.24}{0.26}=0.923076923077\approx0.923[/tex]
Hence, the conditional probability that an Internet user posts photos that they have taken themselves, given that they post videos that they have taken themselves = 0.923