Question

a hockey player has an acceleration of -3.1 m/s ². How long does it take him to come to a complete stop from a speed of 13 m/s?

Answer 1

Answer:

Explanation:

a = (v-u) / t

-3.1 = -13/t

t = 4.19s

Answer 2

Answer:

A hockey player has an acceleration of -3.1$m/s^2$ to complete at a speed of 13 m/s it takes him 4.2 seconds.

Explanation:

Applying the 1 \mathrm{st}  Equation of Motion

v = u + at

where v = Final Velocity

u = Initial Velocity

a = acceleration

t = time

Given-

v = 0 m/s (Complete stop)

u = +13 m/s

a =  -3.1$\mathrm{m} / \mathrm{s}^{2}$ (negative shows deceleration)

Putting the Values

0 = 13 + (-3.1)t

or, 3.1t = 13

or, t= $\frac{130}{31}$

or, t = 4.1935 seconds = 4.2 s