Question

Write a function that accepts an int array and the array’s size as arguments. 1. The function should create a new array that is twice the size of the argument array. 2. The function should copy the contents of the argument array to the new array, and initialize the unused elements of the second array with 0. 3. The function should return a pointer to the new array. Demonstrate the function by using it in a main program that reads

Answer 1

Answer:

The question seems to be incomplete. Analyzing the full question the answer has been explained below. Please let me know if your answer requirement was other than this.

Explanation:

#include<iostream>

#include<fstream>

using namespace std;

int *extend(int arr[], int N)

{

  // create a new array that is twice

  //the size of the argument array.

  int *new_arr = new int[2 * N];

  int i;

  // copy the contents of the argument

  //array to the new array

  for (i = 0; i < N; i++)

      new_arr[i] = arr[i];

  // initialize the unused elements

  //of the second array with 0

  for (i = N; i < 2 * N; i++)

      new_arr[i] = 0;

  // return a pointer to the new array

  return new_arr;

}

//main function

int main()

{

  // Declare the array

  int N;

  //Prompt and reads an integer N

  cout << "Enter N : ";

  cin >> N;

  // If the integer read in from

  //standard input exceeds 50 or is less than 0

  if (N < 0 || N > 50)

      // The program terminates silently

      exit(0);

  // open file in read mode

  ifstream in("data.txt");

  // create an array of size N

  int *arr = new int[N];

  int i;

  // reads N integers from a file

  //named data into an array

  for (i = 0; i < N; i++)

  {

      // read integer from file

      in >> arr[i];

  }

  //then passes the array to your

  //array expander function

  int *new_arr = extend(arr, N);

  // print the extended array

  for (i = 0; i < 2 * N; i++)

      cout << new_arr[i] << endl;

  in.close();

  return 0;

}