Answer:
P = f(TLTL) = 0,16
H = f(TLTS) = 0,48
Q = f(TSTS) = 0,36
Explanation:
Hello!
The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).
The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.
In this case, let's say:
f(TL) = p
f(TS) = q
p + q = 1
Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:
TL= 0,4
TS= 0,6
Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.
P = f(TLTL)
H = f(TLTS)
Q = f(TSTS)
Also P + H + Q = 1
And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:
[tex]p^{2} = f(TLTL)[/tex]
[tex]2pq = f(TSTL)[/tex]
[tex]q^{2} = f(TSTS)[/tex]
So, if the population is in balance:
[tex]P = p^{2}[/tex]
[tex]H = 2pq[/tex]
[tex]Q = q^{2}[/tex]
Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:
[tex]f(TLTL) = P = p^{2} = 0,4^{2} = 0,16[/tex]
[tex]f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48[/tex]
[tex]f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36[/tex]
I hope you have a SUPER day!