Question

A large fish hangs from a spring balance supported from the roof of an elevator. If the elevator has an upward acceleration of 2.45 m/s
2 and the balance reads 60.0 N, what is the true weight of the fish?

Answer 1

Answer:

Original Weight = 48 N

Explanation:

When an object hanging from the roof of an elevator and the elevator moves upward with a certain acceleration say a, then the observe weight is always greater than the actual weight.

And when elevator moves downward direction with acceleration a, then the observe weight is always lesser than the actual weight.

Given data:

a = 2.45 m/s²

Balance reading = Tension = T = 60 N

As elevator moves upward,

So,

               T = m(g + a)

         60 N = m(9.81 + 2.45)

               m = 60/12.26

               m = 4.89 kg

This is the original mass of the hanging fish.

We know that

                Weight = W = mg

                                W = 4.89 × 9.81

                                W = 48 N

       

Answer 2

The real weight of the fish is equal to 48N.

Weight strength and normal strength

To resolve this issue, one must consider the action of two forces, the weight force and the normal force.

In the case of the question, we have a fish being weighed in an elevator accelerating upwards, that is, the force that the balance will measure will be:

                                         $F_n = m \times (g+a)$

So, applying the given values ​​we have:

                                       $60 = m (9.81 \times 2.45)$

                                             $m = 4.89kg$

Finally, to find the weight of the fish, simply multiply the value of the mass by gravity, so that:

                                       $F = 4.89 \times 9.81 = 48N$

So, the real weight of the fish is equal to 48N.

Learn more about weight strength in: brainly.com/question/10922298