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A special standard weight, known to weight 10 N to high accuracy, is used to check the accuracy of two spring scales. On the first scale the weight gives a reading of 8.4 N. On the second scale the weight gives a reading of 9.1 N. The percent difference between the measurements of the two scales is %. (Never negative.)

Respuesta :

Answer:

16 % and 9 %

Explanation:

Accurate reading = 10 N

reading of first balance = 8.4 N

reading of second balance = 9.1 N

Percentage difference in first reading

= [tex]\frac{True reading - reading of first balance}{True reading}\times 100 %[/tex]

= [tex]\frac{10-8.4}{10}\times 100 %[/tex] = 16 %

Percentage difference in second reading

= [tex]\frac{True reading - reading of second balance}{True reading}\times 100 %[/tex]

= [tex]\frac{10-9.1}{10}\times 100 %[/tex] = 9 %

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