Answer:
It is a discrete distribution of probability, with mean = 0.879 and SD = 0.787.
Step-by-step explanation:
With the given data, it can be said we have a discrete distribution of probability.
Calculation of the mean
[tex]\bar{X}=\sum_{i=0}^{3} P(x_{i})*x_{i} = 0.354*0+0.436*1+0.187*2+0.023*3=0.879[/tex]
Calculation of the standard deviation
[tex]sd=\sqrt{\sum_{i=0}^{3} P(x_{i})*(x_{i}-\bar{x})^{2} } \\\\sd= \sqrt{0.354*(0-0.879)^{2} +0.436*(1-0.879)^{2}+0.187*(2-0.879)^{2}+0.023*(3-0.879)^{2}}\\\\sd=\sqrt{0.354*0.773 +0.436*0.015+0.187*1.257+0.023*4.499}\\\\sd=\sqrt{0.619}=0.787[/tex]