Respuesta :
Answer:
we know,
in rectangle
area(a)=l*b
(a)so width (b)=a/l
=3600 m^2/90 m
=40m
(b) in square,
area(a)=l^2
or,3600 m^2=l^2
or,(60m)^2=l^2
cancelling square
length (l)=60m
(c) perimeter =2 (l+b)
let width be x so l is rd
or,3600m=2 (x+5x)
or,3600m/2=6x
or,1800m/6=x
or,300m=x (width) and length =5*x
Answer:
Part a) The width of the rectangular banquet hall is 40 m
Part b) The length of the square room is 60 m
Part c) The width of the third rectangular banquet hall is 300 m
Step-by-step explanation:
Part a) What is the width of the banquet hall?
Let
L ----> the length of the rectangular banquet hall
W ---> the width of the rectangular banquet hall
we know that
The area of a rectangle is equal to
[tex]A=LW[/tex]
we have
[tex]A=3,600\ cm^2[/tex]
[tex]L=90\ m[/tex]
substitute the values and solve for W
[tex]3,600=(90)W[/tex]
[tex]W=3,600/(90)[/tex]
[tex]W=40\ m[/tex]
therefore
The width of the rectangular banquet hall is 40 m
Part b) A square banquet hall has the same area. What is the length of the room?
we know that
The area of a square is
[tex]A=L^2[/tex]
we have
[tex]A=3,600\ cm^2[/tex]
substitute and solve for L
[tex]3,600=L^2[/tex]
take the square root both sides
[tex]L=60\ m[/tex]
therefore
The length of the square room is 60 m
Part c) A third rectangular banquet hall has a perimeter of 3,600 m. What is the width if the length is 5 times the width?
Let
L ----> the length of the third rectangular banquet hall
W ---> the width of the third rectangular banquet hall
we know that
The perimeter of a rectangle is equal to
[tex]P=2(L+W)[/tex]
[tex]3,600=2(L+W)[/tex]
simplify
[tex]1,800=(L+W)[/tex] -----> equation A
[tex]L=5W[/tex] ------> equation B
substitute equation B in equation A and solve for W
[tex]1,800=(5W+W)[/tex]
[tex]1,800=6W[/tex]
[tex]W=300\ m[/tex]
therefore
The width of the third rectangular banquet hall is 300 m