The floor of a rectangular banquet hall has an area of 3,600 m². The length is 90 m.
a. What is the width of the banquet hall?
b. A square banquet hall has the same area. What is the length of the room?
c. A third rectangular banquet hall has a perimeter of 3,600 m. What is the width if the length is 5 times the width?

Respuesta :

Answer:

we know,

in rectangle

area(a)=l*b

(a)so width (b)=a/l

=3600 m^2/90 m

=40m

(b) in square,

area(a)=l^2

or,3600 m^2=l^2

or,(60m)^2=l^2

cancelling square

length (l)=60m

(c) perimeter =2 (l+b)

let width be x so l is rd

or,3600m=2 (x+5x)

or,3600m/2=6x

or,1800m/6=x

or,300m=x (width) and length =5*x

Answer:

Part a) The width of the rectangular banquet hall is 40 m

Part b) The length of the square room is 60 m

Part c) The width of the third rectangular banquet hall is 300 m

Step-by-step explanation:

Part a) What is the width of the banquet hall?

Let

L ----> the length of the rectangular banquet hall

W ---> the width of the rectangular banquet hall

we know that

The area of a rectangle is equal to

[tex]A=LW[/tex]

we have

[tex]A=3,600\ cm^2[/tex]

[tex]L=90\ m[/tex]

substitute the values and solve for W

[tex]3,600=(90)W[/tex]

[tex]W=3,600/(90)[/tex]

[tex]W=40\ m[/tex]

therefore

The width of the rectangular banquet hall is 40 m

Part b) A square banquet hall has the same area. What is the length of the room?

we know that

The area of a square is

[tex]A=L^2[/tex]

we have

[tex]A=3,600\ cm^2[/tex]

substitute and solve for L

[tex]3,600=L^2[/tex]

take the square root both sides

[tex]L=60\ m[/tex]

therefore

The length of the square room is 60 m

Part c) A third rectangular banquet hall has a perimeter of 3,600 m. What is the width if the length is 5 times the width?

Let

L ----> the length of the third rectangular banquet hall

W ---> the width of the third rectangular banquet hall

we know that

The perimeter of a rectangle is equal to

[tex]P=2(L+W)[/tex]

[tex]3,600=2(L+W)[/tex]

simplify

[tex]1,800=(L+W)[/tex] -----> equation A

[tex]L=5W[/tex] ------> equation B

substitute equation B in equation A and solve for W

[tex]1,800=(5W+W)[/tex]

[tex]1,800=6W[/tex]

[tex]W=300\ m[/tex]

therefore

The width of the third rectangular banquet hall is 300 m

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