Question

The scores of an eighth-grade math test have a normal distribution with a mean u = 83 and a standard deviation o = 5. If
Din's test score was 92, which expression would she write to find the Z-score of her test score?
92-83
O2- 83
5
O z: 83-92
O z- 92-83
0
92

Answer 1

Answer:

$z=\frac{92-83}{5}$

Step-by-step explanation:

* Lets explain how to find the z-score

- If the data have normal distribution with a mean μ and a standard

 deviation σ and we need to find the z-score for score x,then

 $z=\frac{x-u}{o}$

* Lets solve the problem

- The scores of an eighth-grade math test have a normal distribution

- The mean is 83

- The standard deviation is 5

- Din's test score was 92

- We need to find z-score of Din's test score

∵ x = 92

∵ μ = 83

∵ σ = 5

∴ $z=\frac{92-83}{5}$

Answer 2

Answer:

92-83/5

Step-by-step explanation: