Question

On a coordinate plane, square A B C D is shown. Point A is at (3, 4), point B is at (2, negative 2), point C is at (negative 4, negative 1), and point D is at (negative 3, 5). What is the perimeter of square ABCD? StartRoot 37 EndRoot units 4 StartRoot 37 EndRoot units 28 units 37 units

Answer 1

Answer:

  4√37 units

Step-by-step explanation:

Side AB has a length given by the distance formula:

  d = √((x2-x1)² +(y2-y1)²)

  d = √((2-3)² +(-2-4)) = √(1+36) = √37

The perimeter of the square is the sum of the lengths of four sides that are this length, so is ...

  P = 4d = 4√37 . . . units

Answer 2

Answer:

B) $4\sqrt{37}$ units

Step-by-step explanation:

perimeter = side lengths added together

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