We are asked to solve and determine how many imaginary and real zeroes in the given expression shown below:
f(x) = x3 + 5x2 -28x - 32
We need to perform factorization of (x+1) from the given function such that the problem become:
x3 + 5x2 - 28x - 32
(x+1) (x2 + 4x -32) , now we need to perform factorization of (x2 + 4x - 32)
this can be a combination of numbers +8 and -4 such that
(x+1) (x+8)(x-4)
From the solution, we clearly see that there were three real zeroes in the given function.
The answer is "0 imaginary, 3 real".
