Answer:
0.006593
Step-by-step explanation:
Let K be the number of possibilities that 3 parts can be chosen randomly from among 15.
K is the combination of 15 taken 3 at a time
[tex]\binom{15}{3}=\frac{15!}{3!(15-3)!}=\frac{15!}{3!12!}=\frac{15.14.13}{6}=455[/tex]
Of this 455 possibilities of choosing 3 parts, only 3 can have exactly one nonconforming part.
So the probability of finding three parts with exactly one defective is
[tex]\frac{3}{455}=0.006593\approx 0.65\%[/tex]