Respuesta :
Answer:
1) Mother Type M, A and Father Type N
4) Mother Type MN, O and Father Type MN, A-
Explanation:
We have three loci in this problem with different alleles possible:
M/N alleles are codominant.
A/B/O alleles, being A and B codominant while O is recessive.
Rh factor: +/- positive (+) is dominant over negative (-) allele.
The child phenotype is: MN, A+.
This means at least on of the parents had to have one allele M, one N, one A and one positive (+).
The options given are phenotypes, not genotypes:
1) Mother (M): M, A and Father (F): N, B- .
This couple could be the parents. Mom´s genotype could be MM, AA,++ and dad´s one: NN,BO,-- .
2) M: MN,AB- and F: M,O-.
In this case the kid could not be their child. Both parents are Rh negative. That means their genotype has to be --. And the kid has at least one positive allele.
3) M: MN, B+ and F: N,O+
In this case the child cannot be theirs either. A is dominant and neither parent has it in their phenotype.
4) M: MN, O+ and F: MN, A-
This couple could also be parents of the child, moms genotype could be MN, OO,++ while the father could be MN, AO, --
They have at least on allele of the childs phenotype: MN, A, +
5) None of these.
False, we already identified two possible parents.
Correct answer: 1 and 4
A child MN may be due to the following combinations 'Mother M, A and Father N' or 'Mother MN, O and Father MN, A-'
- In humans, the MN is a blood group under the control of co-dominant alleles called LM and LN.
- Codominance refers to the genetic phenomena in which both alleles are expressed in a heterozygous individual.
- A heterozygous individual for the MN blood group will have both M and N alleles.
In conclusion, a child MN may be due to the following combinations 'Mother M, A and Father N' or 'Mother MN, O and Father MN, A-'
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