Question

Consider two regions of space containing a static electric field, region A and region B. In region A the equipotential lines are more closely spaced than those in region B. What can be said about the relative strength of the electric field in the two regions

Answer 1

Answer:

The electric field of region A is stronger than the electric field of region B.

Explanation:

The expression for the electric field at a point is define by the formula,

$E=\frac{kq}{r^{2} }$

Here, r is the distance between the two charges.

Therefore,

$E\alpha \frac{1}{r^{2} }$

Here, electric field is inversely proportional to the square of the distance between the two charges.

Hence, smaller the distance between the charges, more will be the electric field.

According to the given situation, two regions A and B containing a static electric field, in region A the equipotential lines are closely bound than the region B.

Therefore electric field of region A is stronger than the electric field of region B.

Answer 2

The strength of the effect of the force of static electric field on region A in another region B is known as the relative strength of the electric field. The relative strength in region B be will be weaker than the field in region A.

What is an electric field?

It is a physical field occupied by a charged particle on another particle in its surrounding.

The relation of the electric field with the distance between the charged particle is given by the formula

$E= \frac{Kq }{R^{2} }$

Where R is the spacing between the equipotential line.

Electric field intensity is inversly proportional to the square of the distance.

The equipotential lines are more closely packed in region A than the equipotential lines in region B. Therefore the relative strength of region B  be will be weaker than the field in region A.

To learn more about the electric force refer to the link;

brainly.com/question/1076352