Question

Using the Acceleration Equation
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A cyclist going downhill is accelerating at 1.2 m/s2. If the final velocity of the cyclist is 16 m/s
is the cyclist's initial velocity?
o oo
0 4 m/s
O 12 m/s
O 18 m/s
O 20 m/s

Answer 1

Answer:

Change in velocity (\Delta v) is acceleration (a) times time (t)

Acceleration a=1.2\ m/s^{2}

Time t=10\ s

So \Delta v=at=1.2\ m/s^{2}*10\ s=12\ m/s

The initial velocity is then 16\ m/s-12\ m/s=4\ m/s

Easy Answer: 4m/s

Explanation: